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First solution in Clear category for Roman Numerals by frach
def checkio(data):
thousands = ('','M','MM','MMM','MMMM')
hundreds = ('','C','CC','CCC','CD','D','DC','DCC','DCCC','CM')
tens = ('','X','XX','XXX','XL','L','LX','LXX','LXXX','XC')
jedn = ('','I','II','III','IV','V','VI','VII','VIII','IX')
newdata = str(data).zfill(4)
return thousands[int(newdata[0])] + hundreds[int(newdata[1])] + tens[int(newdata[2])] + jedn[int(newdata[3])]
Oct. 29, 2015
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