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First solution in Clear category for Roman Numerals by cinekk
def checkio(data):
result = ""
ints = (1000,900,500,400,100,90,50,40,10,9,5,4,1)
nums = ('M','CM','D','CD','C','XC','L','XL','X','IX','V','IV','I')
for i in range(len(ints)):
count = int(data/ints[i])
result += nums[i] * count
data -= ints[i] * count
#replace this for solution
return result
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio(6) == 'VI', '6'
assert checkio(76) == 'LXXVI', '76'
assert checkio(499) == 'CDXCIX', '499'
assert checkio(3888) == 'MMMDCCCLXXXVIII', '3888'
Nov. 20, 2016