Check it !!!!!! Not bad, I think)) clear solution for Roman Numerals by Sergey_Kolomoets - python coding challenges

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Check it !!!!!! Not bad, I think)) solution in Clear category for Roman Numerals by Sergey_Kolomoets

def checkio(data):
    r = {1000: "M", 900: "CM", 500: "D", 400: "CD", 100: "C", 90: "XC", 50: "L",
    40: "XL", 10: "X", 9: "IX", 5: "V", 4: "IV", 1: "I"}
    res = ''
    for i in r:
        l, k = divmod(data, i)
        data = k
        res += str(r[i] * l)
    return res
if __name__ == '__main__':
    #These "asserts" using only for self-checking and not necessary for auto-testing
    assert checkio(6) == 'VI', '6'
    assert checkio(76) == 'LXXVI', '76'
    assert checkio(499) == 'CDXCIX', '499'
    assert checkio(3888) == 'MMMDCCCLXXXVIII', '3888'

Feb. 15, 2017

Comments:

rob.treharne on Feb. 15, 2017, 3:02 p.m.
Woah. Nice.

Sergey_Kolomoets on Feb. 15, 2017, 3:03 p.m.
Thank you)

R2R on Feb. 21, 2017, 9:16 p.m.
Good job! I like it!

veky on Feb. 22, 2017, 6:20 p.m.
Why `str`? And why not simply <pre class='brush: python'>l, data = divmod(...) </pre>

Shmebula on Feb. 24, 2017, 3:04 a.m.
Thanks for the highlight of divmod. There are so many built-in functions I never paid attention to and end up recreating all the time. :)

veky on Feb. 24, 2017, 5:32 a.m.
Whenever you try to write some new functionality, stop. And think, of the enormous number of Pythonistas in the world, am I really the first one that needed this? :-)

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