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First solution in Clear category for Roman Numerals by Sara_Pinela
def checkio(data):
import math
U= ['','I','II','III','IV','V','VI','VII','VIII','IX']
D= ['','X','XX','XXX','XL','L','LX','LXX','LXXX','XC']
C= ['','C','CC','CCC','CD','D','DC','DCC','DCCC','CM']
mil= data//1000
numromano=''
numromano+= 'M'* mil
u= data%10
d= int(math.floor(data/10))%10
c=int(math.floor(data/100))%10
if (data>=100):
numromano+= C[c]+ D[d]+U[u]
elif (data>=10):
numromano+= D[d]+U[u]
else:
numromano+= U[u]
return numromano
#replace this for solution
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio(6) == 'VI', '6'
assert checkio(76) == 'LXXVI', '76'
assert checkio(499) == 'CDXCIX', '499'
assert checkio(3888) == 'MMMDCCCLXXXVIII', '3888'
Jan. 18, 2017
