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First solution in Clear category for Roman Numerals by Geovanna_M_Gomez
def checkio(data):
import math
unidades= ['','I','II','III','IV','V','VI','VII','VIII','IX']
decenas= ['','X','XX','XXX','XL','L','LX','LXX','LXXX','XC']
centenas= ['','C','CC','CCC','CD','D','DC','DCC','DCCC','CM']
miles= data//1000
romano=''
romano+= 'M'* miles
uni= data%10
dece= int(math.floor(data/10))%10
cen=int(math.floor(data/100))%10
if (data>=100):
romano+= centenas[cen]+ decenas[dece]+unidades[uni]
elif (data>=10):
romano+=decenas[dece]+unidades[uni]
else:
romano+= unidades[uni]
return romano
#replace this for solution
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio(6) == 'VI', '6'
assert checkio(76) == 'LXXVI', '76'
assert checkio(499) == 'CDXCIX', '499'
assert checkio(3888) == 'MMMDCCCLXXXVIII', '3888'
Jan. 10, 2017
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