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First solution in Clear category for Roman Numerals by BowAnArrow
def checkio(data):
data=str(data)
Roman_numerals=[{'1':'M','2':'MM','3':'MMM'},
{'1':'C','2':'CC','3':'CCC','4':'CD','5':'D','6':'DC','7':'DCC','8':'DCCC','9':'CM','0':''},
{'1':'X','2':'XX','3':'XXX','4':'XL','5':'L','6':'LX','7':'LXX','8':'LXXX','9':'XC','0':''},
{'1':'I','2':'II','3':'III','4':'IV','5':'V','6':'VI','7':'VII','8':'VIII','9':'IX','0':''}]
Answer=""
j=4-len(data)
for i in data:
Answer+=Roman_numerals[j][i]
j+=1
return Answer
'''
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio(6) == 'VI', '6'
assert checkio(76) == 'LXXVI', '76'
assert checkio(499) == 'CDXCIX', '499'
assert checkio(3888) == 'MMMDCCCLXXXVIII', '3888'
print('Done! Go Check!')
'''
Oct. 20, 2018
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