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First solution in Clear category for Reverse Every Ascending by mortonfox
from itertools import groupby, chain
class GroupbyHelper:
def __init__(self):
self.lastval = None
self.i = 0
def __call__(self, val):
if self.lastval is not None and val <= self.lastval:
self.i += 1
self.lastval = val
return self.i
def reverse_ascending(items):
return chain.from_iterable(reversed(list(g)) for _, g in groupby(items, GroupbyHelper()))
if __name__ == '__main__':
print("Example:")
print(reverse_ascending([1, 2, 3, 4, 5]))
# These "asserts" are used for self-checking and not for an auto-testing
assert list(reverse_ascending([1, 2, 3, 4, 5])) == [5, 4, 3, 2, 1]
assert list(reverse_ascending([5, 7, 10, 4, 2, 7, 8, 1, 3])) == [10, 7, 5, 4, 8, 7, 2, 3, 1]
assert list(reverse_ascending([5, 4, 3, 2, 1])) == [5, 4, 3, 2, 1]
assert list(reverse_ascending([])) == []
assert list(reverse_ascending([1])) == [1]
assert list(reverse_ascending([1, 1])) == [1, 1]
assert list(reverse_ascending([1, 1, 2])) == [1, 2, 1]
print("Coding complete? Click 'Check' to earn cool rewards!")
Dec. 6, 2018