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First solution in Clear category for Restricted Sum by wojtek96
def plus(numbers):
result = 0
if len(numbers) == 0:
result = 0
else:
result = numbers[-1]
numbers.pop()
result = result + plus(numbers)
return result
def checkio(data):
s = 0
s = (plus(data))
return s
Dec. 15, 2016