Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
First solution in Clear category for Restricted Prime by kazuki.h
def checkio(number):
l = ["a", "b"]
zero = l.index("a")
one = l.index("b")
i = ["", "a", "b"].index("b")
while i < number:
j = ["", "a", "b"].index("b")
i += one
while i * j <= number:
if i * j == number:
return False
j += one
return i == number
Nov. 25, 2021
