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First solution in Clear category for Remove All Before by Denis_Donner
from collections.abc import Iterable
def remove_all_before(items: list, border: int) -> Iterable:
# print(items[items.index(border):])
if border not in items:
return items
else:
return items[items.index(border):]
print("Example:")
# print(list(remove_all_before([1, 2, 3, 4, 5], 3)))
print(list(remove_all_before([1, 2, 3, 4, 5], 3)))
# These "asserts" are used for self-checking
assert list(remove_all_before([1, 2, 3, 4, 5], 3)) == [3, 4, 5]
assert list(remove_all_before([1, 1, 2, 2, 3, 3], 2)) == [2, 2, 3, 3]
assert list(remove_all_before([1, 1, 2, 4, 2, 3, 4], 2)) == [2, 4, 2, 3, 4]
assert list(remove_all_before([1, 1, 5, 6, 7], 2)) == [1, 1, 5, 6, 7]
assert list(remove_all_before([], 0)) == []
assert list(remove_all_before([7, 7, 7, 7, 7, 7, 7, 7, 7], 7)) == [
7,
7,
7,
7,
7,
7,
7,
7,
7,
]
print("The mission is done! Click 'Check Solution' to earn rewards!")
April 3, 2023
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