Remove All Before

Remove All Before


Not all of the elements are important. What you need to do here is to remove from the sequence all of the elements before the given one.


For the illustration we have a sequence [1, 2, 3, 4, 5] and we need to remove all elements that go before 3 - which are 1 and 2.

We have two edge cases here: (1) if a cutting element cannot be found, then the sequence shoudn't be changed. (2) if the sequence is empty, then it should remain empty.

Input: List and the border element.

Output: List or another Iterable (tuple, iterator, generator).


assert list(remove_all_before([1, 2, 3, 4, 5], 3)) == [3, 4, 5]
assert list(remove_all_before([1, 1, 2, 2, 3, 3], 2)) == [2, 2, 3, 3]
assert list(remove_all_before([1, 1, 2, 4, 2, 3, 4], 2)) == [2, 4, 2, 3, 4]
assert list(remove_all_before([1, 1, 5, 6, 7], 2)) == [1, 1, 5, 6, 7]
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In order to install CheckiO client you'll need installed Python (version at least 3.8)

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Configure your tool

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checkio serv -d

Alternatevly, you can install Chrome extension or FF addon

checkio install-plugin
checkio install-plugin --ff
checkio install-plugin --chromium

Read more here about other functionality that the checkio client provides. Feel free to submit an issue in case of any difficulties.

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