Remove All After
Not all of the elements are important. What you need to do here is to remove all of the elements after the given one from sequence.
For illustration, we have a sequence [1, 2, 3, 4, 5] and we need to remove all the elements that go after 3 - which are 4 and 5.
We have two edge cases here:
- if a cutting element cannot be found, then the sequence shouldn't be changed;
- if the sequence is empty, then it should remains empty.
Input: List of integers (int).
Output: List or other Iterable (tuple, iterator, generator ...) of integers (int).
Examples:
assert list(remove_all_after([1, 2, 3, 4, 5], 3)) == [1, 2, 3] assert list(remove_all_after([1, 1, 2, 2, 3, 3], 2)) == [1, 1, 2] assert list(remove_all_after([1, 1, 2, 4, 2, 3, 4], 2)) == [1, 1, 2] assert list(remove_all_after([1, 1, 5, 6, 7], 2)) == [1, 1, 5, 6, 7]
CheckiO Extensions allow you to use local files to solve missions. More info in a blog post.
In order to install CheckiO client you'll need installed Python (version at least 3.8)
Install CheckiO Client first:
pip3 install checkio_client
Configure your tool
checkio --domain=py config --key=
Sync solutions into your local folder
checkio sync
(in beta testing) Launch local server so your browser can use it and sync solution between local file end extension on the fly. (doesn't work for safari)
checkio serv -d
Alternatevly, you can install Chrome extension or FF addon
checkio install-plugin
checkio install-plugin --ff
checkio install-plugin --chromium
Read more here about other functionality that the checkio client provides. Feel free to submit an issue in case of any difficulties.
