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union sets solution in Clear category for Rectangles Union by kudinov.feodor
from typing import List, Tuple
def rectangles_union(recs: List[Tuple[int]]) -> int:
res = set()
for x1, y1, x2, y2 in recs:
res |= {(x, y) for x in range(x1, x2) for y in range(y1, y2)}
return len(res)
if __name__ == '__main__':
print("Example:")
print(rectangles_union([
(6, 3, 8, 10),
(4, 8, 11, 10),
(16, 8, 19, 11)
]))
# These "asserts" are used for self-checking and not for an auto-testing
assert rectangles_union([
(6, 3, 8, 10),
(4, 8, 11, 10),
(16, 8, 19, 11)
]) == 33
assert rectangles_union([
(16, 8, 19, 11)
]) == 9
assert rectangles_union([
(16, 8, 19, 11),
(16, 8, 19, 11)
]) == 9
assert rectangles_union([
(16, 8, 16, 8)
]) == 0
assert rectangles_union([
]) == 0
print("Coding complete? Click 'Check' to earn cool rewards!")
March 19, 2022