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unique bottom-left coordinate 1x1 solution in Clear category for Rectangles Union by PetrStar
from typing import List, Tuple
def rectangles_union(recs: List[Tuple[int]]) -> int:
# slice every rectangle by 1x1 and remember bottom-left coordinate (count these cordinates = area)
return len({(xi, yi) for rec in recs for xi in range(rec[0], rec[2]) for yi in range(rec[1], rec[3])})
if __name__ == '__main__':
print("Example:")
print(rectangles_union([
(6, 3, 8, 10),
(4, 8, 11, 10),
(16, 8, 19, 11)
]))
# These "asserts" are used for self-checking and not for an auto-testing
assert rectangles_union([
(6, 3, 8, 10),
(4, 8, 11, 10),
(16, 8, 19, 11)
]) == 33
assert rectangles_union([
(16, 8, 19, 11)
]) == 9
assert rectangles_union([
(16, 8, 19, 11),
(16, 8, 19, 11)
]) == 9
assert rectangles_union([
(16, 8, 16, 8)
]) == 0
assert rectangles_union([
]) == 0
print("Coding complete? Click 'Check' to earn cool rewards!")
Dec. 6, 2020