Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
Dumb solution solution in Clear category for Probably Dice by CDG.Axel
def probability(dice_number, sides, target):
comb = {i + 1: 1 for i in range(sides)}
for i in range(1, dice_number):
nc = {}
for c in comb:
for j in range(sides):
nc[c + j + 1] = nc.get(c + j + 1, 0) + comb[c]
comb = nc
return comb[target] / sides ** dice_number if target in comb else 0
if __name__ == '__main__':
#These are only used for self-checking and are not necessary for auto-testing
def almost_equal(checked, correct, significant_digits=4):
precision = 0.1 ** significant_digits
return correct - precision < checked < correct + precision
assert(almost_equal(probability(2, 6, 3), 0.0556)), "Basic example"
assert(almost_equal(probability(2, 6, 4), 0.0833)), "More points"
assert(almost_equal(probability(2, 6, 7), 0.1667)), "Maximum for two 6-sided dice"
assert(almost_equal(probability(2, 3, 5), 0.2222)), "Small dice"
assert(almost_equal(probability(2, 3, 7), 0.0000)), "Never!"
assert(almost_equal(probability(3, 6, 7), 0.0694)), "Three dice"
assert(almost_equal(probability(10, 10, 50), 0.0375)), "Many dice, many sides"
Nov. 8, 2021