Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
Linear Solution solution in Clear category for Popular Words by ostap.bender.ac
def popular_words(text: str, words: list) -> dict:
text1 = text.lower()
print(text1)
d = text1.split('\n') # Clean all '\n' symbols
S = ''
S = ' '.join(d) # Get a string combined without '\n'
d=S.split(' ') # list, just count words in list
res_dict = {}
counter = 0
for w in words:
for k in d:
if w == k:
counter += 1
res_dict.update({w: counter})
counter = 0
return res_dict
if __name__ == '__main__':
print("Example:")
print(popular_words('''
When I was One
I had just begun
When I was Two
I was nearly new
''', ['i', 'was', 'three', 'near']))
# These "asserts" are used for self-checking and not for an auto-testing
assert popular_words('''
When I was One
I had just begun
When I was Two
I was nearly new
''', ['i', 'was', 'three', 'near']) == {
'i': 4,
'was': 3,
'three': 0,
'near': 0
}
print("Coding complete? Click 'Check' to earn cool rewards!")
March 2, 2022