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First solution in Clear category for Popular Words by guita
def popular_words(text: str, words: list) -> dict:
# Clean the text and transform it to a list
text=text.lower().replace('\n', ' ')
text=text.split()
# Create a dictionary with values=0 for each element of "words"
my_count={}
my_set=set(words)
for el in my_set:
my_count[el]=0
# Count number of appearances of each element of "words" in "text"
for el in text:
if el in my_set:
my_count[el]+=1
# Return the dictionary with word counts
return my_count
if __name__ == '__main__':
print("Example:")
print(popular_words('''
When I was One
I had just begun
When I was Two
I was nearly new
''', ['i', 'was', 'three', 'near']))
# These "asserts" are used for self-checking and not for an auto-testing
assert popular_words('''
When I was One
I had just begun
When I was Two
I was nearly new
''', ['i', 'was', 'three', 'near']) == {
'i': 4,
'was': 3,
'three': 0,
'near': 0
}
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May 9, 2021