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Second (='ω'=) solution in Clear category for Popular Words by Magu
import re
import collections as c
def popular_words(text: str, words: list) -> dict:
return {key:c.Counter(re.split('[\s]', text.lower()))[key] for key in words}
if __name__ == '__main__':
print("Example:")
print(popular_words('''
When I was One
I had just begun
When I was Two
I was nearly new
''', ['i', 'was', 'three', 'near']))
# These "asserts" are used for self-checking and not for an auto-testing
assert popular_words('''
When I was One
I had just begun
When I was Two
I was nearly new
''', ['i', 'was', 'three', 'near']) == {
'i': 4,
'was': 3,
'three': 0,
'near': 0
}
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Sept. 9, 2021