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1line solution in Clear category for Pawn Brotherhood by wooilkim
def safe_pawns(pawns: set) -> int:
return len({pawn for pawn in pawns
if (chr(ord(pawn[0]) + 1) + str(int(pawn[1]) - 1)) in pawns
or (chr(ord(pawn[0]) - 1) + str(int(pawn[1]) - 1)) in pawns})
May 27, 2021
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