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First solution in Clear category for Pawn Brotherhood by gsbullmer
def safe_pawns(pawns):
"""
Return the number of pawns defended by another pawn.
"""
def is_safe(pawn):
"""
Determine the defending pawns' spaces and return if any of them
are in the pawns list.
"""
back_rank = str(int(pawn[1]) - 1)
left_file = chr(ord(pawn[:1]) - 1)
right_file = chr(ord(pawn[:1]) + 1)
defenders = {
"".join([left_file, back_rank]),
"".join([right_file, back_rank])
}
return True if defenders & pawns else False
safe = [is_safe(pawn) for pawn in pawns]
return safe.count(True)
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert safe_pawns({"b4", "d4", "f4", "c3", "e3", "g5", "d2"}) == 6
assert safe_pawns({"b4", "c4", "d4", "e4", "f4", "g4", "e5"}) == 1
July 20, 2017
