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First solution in Clear category for Pawn Brotherhood by Valiko_Porosyuko
def safe_pawns(pawns: set) -> int:
s = {'a':1, 'b':2, 'c':3, 'd': 4, 'e': 5, 'f': 6, 'g': 7, 'h': 8}
d = []
count = 0
for x in pawns:
d.append((s[x[0]], int(x[1])))
for x,y in d:
if (x-1, y-1) in d or (x+1, y-1) in d:
count += 1
return count
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert safe_pawns({"b4", "d4", "f4", "c3", "e3", "g5", "d2"}) == 6
assert safe_pawns({"b4", "c4", "d4", "e4", "f4", "g4", "e5"}) == 1
print("Coding complete? Click 'Check' to review your tests and earn cool rewards!")
June 14, 2021