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Chr/ord & str/int solution in Clear category for Pawn Brotherhood by Striga
def safe_pawns(pawns: set) -> int:
count = 0
for i in pawns:
left = chr(ord(i[0])-1) + str(int(i[1])-1)
right = chr(ord(i[0])+1) + str(int(i[1])-1)
if left in pawns or right in pawns:
count += 1
return count
if __name__ == '__main__':
assert safe_pawns({"b4", "d4", "f4", "c3", "e3", "g5", "d2"}) == 6
assert safe_pawns({"b4", "c4", "d4", "e4", "f4", "g4", "e5"}) == 1
Oct. 25, 2020