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First solution in Clear category for Pawn Brotherhood by MihaylovNikitos
def safe_pawns(pawns):
def pawn_friends(coord):
return {
chr(ord(coord[0])-1) + str(int(coord[1])-1),
chr(ord(coord[0])+1) + str(int(coord[1])-1),
}
return sum([True for pawn in pawns if pawns&pawn_friends(pawn)])
Dec. 31, 2015