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Boring solution in Clear category for Pangram by Vulwsztyn
def check_pangram(text):
text=text.upper()
tab=[0]*26
print(tab)
for letter in text:
if ord(letter)>64 and ord(letter)<91:
tab[ord(letter)-65]=1
print(tab)
s=0
for i in tab:
if i!=1:
s=1
break
if s==0:
return True
else:
return False
Oct. 26, 2016