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First solution in Clear category for Pangram by McRawicz
def check_pangram(text):
alfabet=['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']
text=text.lower()
literki=""
for i in text:
if ord(i)>=97 and ord(i)<=122:
if literki.find(i)==-1:
literki+=i
literki=sorted(literki)
if literki==alfabet:
return True
return False
Nov. 5, 2016