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Pangram solution in Clear category for Pangram by KacperBeisert
def check_pangram(text):
lower = text.lower()
result = set()
for item in lower:
if 'a' <= item <= 'z':
result.add(item)
if len(result)==26:
return True
else:
return False
return len({i.lower() for i in text if 'a' <= i.lower() <= 'z'}) == 26
if __name__ == '__main__':
# These "asserts" using only for self-checking and not necessary for auto-testing
assert check_pangram("The quick brown fox jumps over the lazy dog."), "brown fox"
assert not check_pangram("ABCDEF"), "ABC"
assert check_pangram("Bored? Craving a pub quiz fix? Why, just come to the Royal Oak!"), "Bored?"
Dec. 4, 2015