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Concise algorithm solution in Speedy category for Pangram by Igor_Sekretarev
def check_pangram(text: str) -> bool:
return len({ch for ch in text.lower() if ch.isalpha()}) == 26
if __name__ == '__main__':
# These "asserts" using only for self-checking and not necessary for auto-testing
assert check_pangram("The quick brown fox jumps over the lazy dog."), "brown fox"
assert not check_pangram("ABCDEF"), "ABC"
assert check_pangram("Bored? Craving a pub quiz fix? Why, just come to the Royal Oak!"), "Bored?"
print('If it is done - it is Done. Go Check is NOW!')
April 26, 2021
