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First solution in Clear category for Pangram by Elater
def check_pangram(text):
text=text.lower()
sum=0
data=[]
for x in range(0,26):
data.append(0)
for j in range(97,123):
for i in text:
if (ord(i)==j) and (data[j-97]==0):
sum=sum+1
data[j-97]=1
if sum>=26: return True
return False
if __name__ == '__main__':
# These "asserts" using only for self-checking and not necessary for auto-testing
assert check_pangram("The quick brown fox jumps over the lazy dog."), "brown fox"
assert not check_pangram("ABCDEF"), "ABC"
assert check_pangram("Bored? Craving a pub quiz fix? Why, just come to the Royal Oak!"), "Bored?"
Nov. 27, 2016