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Recursion solution in Clear category for Numbers Factory by 9Teen90Three
def checkio(number, a=9, mem = ''):
if a == 1: return 0
if number % a == 0:
b = number / a
if b < 10:
return int(str(int(b))+str(int(a))+mem)
else:
mem = str(a) + mem
return int(str(checkio(b, 9 , mem)))
else:
return checkio(number, a-1, mem)
June 7, 2021
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