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4 Annotated Answers solution in Clear category for Not in Order by BootzenKatzen
# My first solution:
def not_order(data: list[int]) -> int:
ordered = sorted(data) # storing the sorted data in a separate variable
count = 0 # establishing a count variable
for i in range(len(data)): # iterating through the data
if data[i] != ordered[i]: # if the original list item != the sorted item
count +=1 # add to the count of out of order elements
return count # return the count
# My second solution:
def not_order2(data: list[int]) -> int:
return len([data[i] for i in range(len(data)) if data[i] != sorted(data)[i]])
# This is pretty similar logic to my first solution, just in one line
# it creates a list of numbers where the original data != the sorted data
# then len() will return the length of that list - which is the number of out-of-order numbers
# Their solution:
def not_order3(data: list[int]) -> int:
return sum(i != j for i, j in zip(data, sorted(data)))
# i != j will return either true or false depending on what i and j are
# i and j are a pair from data, and sorted(data)
# if the lists are rows of data, zip pulls together the column data
# so the first items from each list are pulled together, and then assigned to i and j
# so if data[0] != sorted(data)[0] i != j and it will return True
# Python reads True as having a value of 1, and False as a value of 0
# so summing together our list of True/False for the data
# will give us the number of True results, which is the number of misplaced items
# Bonus solution:
from operator import ne # ne is a function that checks if 2 things are NOT equal
# so ne(a, b) returns true if a!=b like ne(2, 4) and false if they are like ne(2, 2)
not_order4 = lambda data: sum(map(ne, data, sorted(data)))
# This is basically the same as the solution above
# they just used map to apply ne - comparing two items - to each item in the lists
# rather than zipping the two lists together, and then comparing them, they're doing both at the same time
# then the sum is the same as above.
print("Example:")
print(not_order([1, 1, 4, 2, 1, 3]))
# These "asserts" are used for self-checking
assert not_order([1, 1, 4, 2, 1, 3]) == 3
assert not_order([]) == 0
assert not_order([1, 1, 1, 1, 1]) == 0
assert not_order([1, 2, 3, 4, 5]) == 0
print("The mission is done! Click 'Check Solution' to earn rewards!")
Aug. 25, 2023
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