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First solution in Clear category for Non-unique Elements by aieozn
#Your optional code here
#You can import some modules or create additional functions
def checkio(data):
i=0;
x=0;
wynik=[];
for x in range(len(data)):
liczba=data[x];
y=0;
powt=0;
for y in range(len(data)):
if liczba==data[y]:
powt=powt+1;
if powt>1:
wynik.append(liczba);
print(liczba);
i=i+1;
return wynik;
#Some hints
#You can use list.count(element) method for counting.
#Create new list with non-unique elements
#Loop over original list
if __name__ == "__main__":
#These "asserts" using only for self-checking and not necessary for auto-testing
assert isinstance(checkio([1]), list), "The result must be a list"
assert checkio([1, 2, 3, 1, 3]) == [1, 3, 1, 3], "1st example"
assert checkio([1, 2, 3, 4, 5]) == [], "2nd example"
assert checkio([5, 5, 5, 5, 5]) == [5, 5, 5, 5, 5], "3rd example"
assert checkio([10, 9, 10, 10, 9, 8]) == [10, 9, 10, 10, 9], "4th example"
Nov. 26, 2016