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First solution in Clear category for Non-unique Elements by Rafal.U
#Your optional code here
#You can import some modules or create additional functions
def oblicz(list):
new_list = []
for element in list:
x = list.count(element)
if x > 1 :
new_list.append(element)
list = new_list
return list
def checkio(data):
#Your code here
#It's main function. Don't remove this function
#It's used for auto-testing and must return a result for check.
list = []
new_list = []
list = data
#replace this for solution
data = oblicz(list)
return data
wynik = checkio([1, 2, 3, 1, 3])
#Some hints
#You can use list.count(element) method for counting.
#Create new list with non-unique elements
#Loop over original list
if __name__ == "__main__":
#These "asserts" using only for self-checking and not necessary for auto-testing
assert isinstance(checkio([1]), list), "The result must be a list"
assert checkio([1, 2, 3, 1, 3]) == [1, 3, 1, 3], "1st example"
assert checkio([1, 2, 3, 4, 5]) == [], "2nd example"
assert checkio([5, 5, 5, 5, 5]) == [5, 5, 5, 5, 5], "3rd example"
assert checkio([10, 9, 10, 10, 9, 8]) == [10, 9, 10, 10, 9], "4th example"
Oct. 23, 2016
