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Second (fix removed solution abs(one - i) < abs(one - nearest)) solution in Clear category for Nearest Value by Olpag
def nearest_value(values: set, one: int) -> int:
nearest = max(values)
for i in values:
if abs(one - i) < abs(one - nearest):
nearest = i
elif abs(i - one) == abs(nearest - one):
nearest = i if i < nearest else nearest
return nearest
April 10, 2019