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Simple solution in Clear category for The Most Wanted Letter by u8m_
# migrated from python 2.7
def checkio(text):
s = [s for s in set(text.lower()) if s.islower()]
m = list(map(text.lower().count,s))
return chr(min([ord(s[i]) for i,x in enumerate(m) if x==max(m)]))
Nov. 11, 2015