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collections.Counter with most_common solution in Clear category for The Most Wanted Letter by murray2k
from collections import Counter
import string
def checkio(text):
allowed_items = set(string.ascii_letters)
item_counts = Counter(letter.lower() for letter in text
if letter in allowed_items).most_common()
most_common = [item for item in item_counts if item[1] >= item_counts[0][1]]
most_common.sort()
return most_common[0][0]
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio("Hello World!") == "l", "Hello test"
assert checkio("How do you do?") == "o", "O is most wanted"
assert checkio("One") == "e", "All letter only once."
assert checkio("Oops!") == "o", "Don't forget about lower case."
assert checkio("AAaooo!!!!") == "a", "Only letters."
assert checkio("abe") == "a", "The First."
print("Start the long test")
assert checkio("a" * 9000 + "b" * 1000) == "a", "Long."
print("The local tests are done.")
Aug. 15, 2015