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Simple code solution in Clear category for The Most Wanted Letter by exoarn2
import string
def checkio(text):
text = text.lower() #change all characters to lowercase
lettercount = {}
# count nr. of occurences for all letters in text
for char in text:
if char in lettercount:
lettercount[char] += 1
elif char in string.ascii_letters:
lettercount[char] = 1
# find the key with maximum value, if a simmilar value is found
# for a key lower in the alphabet return that one
max_val = 0
min_char = 'z'
for key,val in lettercount.items():
if val > max_val or (val == max_val and key < min_char):
max_val = val
min_char = key
return min_char
April 4, 2015