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First solution in Clear category for The Most Wanted Letter by e2dyToe
from collections import Counter
import re
def checkio(text):
counts = Counter([x for x in text.lower() if re.search('[a-z]', x) is not None])
max_counts = sorted([x for x in counts if counts[x] == max(counts.values())])
return max_counts[0]
Dec. 30, 2014
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