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First solution in Clear category for The Most Wanted Letter by KlausWang91
from collections import OrderedDict
def checkio(text: str) -> str:
# turn into lower case
lower_text = text.lower()
# delete all special symbols and numbers and turn into a list with seperate letters
final_text_list = list(''.join([i for i in lower_text if i.islower()]))
# create a empty dict
dict = {}
# put all the list elements into the dict like a : 2
for x in final_text_list:
dict.update({x: lower_text.count(x)})
# user OrderedDict to sort the dict by keys to make sure abcdefghijk... order
sorted_dict = OrderedDict(sorted(dict.items()))
# sort the dict by value to output the first element
final_dict = {k: v for k, v in sorted(sorted_dict.items(), key=lambda x: x[1], reverse=True)}
return list(final_dict)[0]
if __name__ == '__main__':
print("Example:")
print(checkio("Hello World!"))
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio("Hello World!") == "l", "Hello test"
assert checkio("How do you do?") == "o", "O is most wanted"
assert checkio("One") == "e", "All letter only once."
assert checkio("Oops!") == "o", "Don't forget about lower case."
assert checkio("AAaooo!!!!") == "a", "Only letters."
assert checkio("abe") == "a", "The First."
print("Start the long test")
assert checkio("a" * 9000 + "b" * 1000) == "a", "Long."
print("The local tests are done.")
if __name__ == '__main__':
print("Example:")
print(checkio("Hello World!"))
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio("Hello World!") == "l", "Hello test"
assert checkio("How do you do?") == "o", "O is most wanted"
assert checkio("One") == "e", "All letter only once."
assert checkio("Oops!") == "o", "Don't forget about lower case."
assert checkio("AAaooo!!!!") == "a", "Only letters."
assert checkio("abe") == "a", "The First."
print("Start the long test")
assert checkio("a" * 9000 + "b" * 1000) == "a", "Long."
print("The local tests are done.")
Feb. 10, 2020
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