Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
One liner with comments solution in Clear category for The Most Wanted Letter by CDG.Axel
from collections import Counter
def checkio(text: str) -> str:
# first - get only letters from source string (filter)
# second - get Counter object that will contain letter and count for letter
# third - sort by 2 argument:
# 1. counter of letter (minus for descending order
# 2. letter (letter with same count sorted in ascending order)
# first in result will be tuple with letter and counter
return sorted(Counter(filter(str.isalpha, text.lower())).items(),
key=lambda x: (-x[1], x[0]))[0][0]
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio("Hello World!") == "l", "Hello test"
assert checkio("How do you do?") == "o", "O is most wanted"
assert checkio("One") == "e", "All letter only once."
assert checkio("Oops!") == "o", "Don't forget about lower case."
assert checkio("AAaooo!!!!") == "a", "Only letters."
assert checkio("abe") == "a", "The First."
print("Start the long test")
assert checkio("a" * 9000 + "b" * 1000) == "a", "Long."
print("The local tests are done.")
Sept. 5, 2021