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min() and max() are your friends. solution in Clear category for The Most Numbers by tigercat2000
def checkio(*args):
# Check if there are no arguments. If there aren't, return 0.
if len(args) == 0:
return 0
# Use the min() function to get the minimum value in the array of arguments.
minN = min(args)
# Use the max() function to get the maximum value in the array of arguments
maxN = max(args)
# Return the maximum value minus the minimum value, therefore giving you the range of the array.
return maxN - minN
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
def almost_equal(checked, correct, significant_digits):
precision = 0.1 ** significant_digits
return correct - precision < checked < correct + precision
assert checkio(-69, 0, 0, -0.051, -0.021, -0.81) == 69, "69"
assert almost_equal(checkio(1, 2, 3), 2, 3), "3-1=2"
assert almost_equal(checkio(5, -5), 10, 3), "5-(-5)=10"
assert almost_equal(checkio(10.2, -2.2, 0, 1.1, 0.5), 12.4, 3), "10.2-(-2.2)=12.4"
assert almost_equal(checkio(), 0, 3), "Empty"
Nov. 5, 2016