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Easy solution in Clear category for The Most Numbers by dominieq
def checkio(*args):
l = len(args)
if l>0:
max=0
min=0
a=args[0]
b=args[0]
for i in range(0, l, 1):
if args[i]>a:
a=args[i]
if args[i]
Nov. 13, 2016