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First solution in Clear category for The Most Numbers by Wojtas1411
def checkio(*args):
if len(args)==0:
return float(0)
else:
maks=float(args[0])
mini=float(args[0])
for i in range(len(args)):
if args[i]>maks:
maks=args[i]
if args[i]
Oct. 23, 2016