Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
First solution in Clear category for The Most Numbers by TurboProNiszczyciel
def checkio(*args):
if not args:
return 0
ret=0
mini=args[0]
maks=args[0]
for i in args:
if i>maks:
maks=i
if i
Dec. 16, 2017