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First solution in Clear category for The Most Numbers by Lukeram
def checkio(*args):
min = 100
max = -100
for i in range(len(args)):
if( args[i] < min ):
min = args[i]
if( args[i] > max ):
max = args[i]
if not (abs(max-min) == 200):
return abs(max-min)
return 0
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
def almost_equal(checked, correct, significant_digits):
precision = 0.1 ** significant_digits
return correct - precision < checked < correct + precision
assert almost_equal(checkio(1, 2, 3), 2, 3), "3-1=2"
assert almost_equal(checkio(5, -5), 10, 3), "5-(-5)=10"
assert almost_equal(checkio(10.2, -2.2, 0, 1.1, 0.5), 12.4, 3), "10.2-(-2.2)=12.4"
assert almost_equal(checkio(), 0, 3), "Empty"
Nov. 9, 2016