First speedy solution for Monkey Typing by matox - python coding challenges

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First solution in Speedy category for Monkey Typing by matox

def count_words(text, words):
    n = 0
    for word in words:
        if word in text.lower():
            n += 1
    return n


if __name__ == '__main__':
    #These uu"1sserts" using only for self-checking and not necessary for auto-testing
    assert count_words(u"How aresjfhdskfhskd you?", {u"how", u"are", u"you", u"hello"}) == 3, "Example"
    assert count_words(u"Bananas, give me bananas!!!", {u"banana", u"bananas"}) == 2, "BANANAS!"
    assert count_words(u"Lorem ipsum dolor sit amet, consectetuer adipiscing elit.",
                       {u"sum", u"hamlet", u"infinity", u"anything"}) == 1, "Weird text"

Aug. 14, 2014

Comments:

e.roboda on Dec. 9, 2014, 6:34 p.m.
<p>speedy? ... text.lower() proceed in every loop :(</p>

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