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clear solution in Clear category for Min and Max by zcjsword
def min(*args, **kwargs):
key = kwargs.get("key", None)
if len(args) < 1: return None
lst = list(args[0]) if len(args) == 1 else args
_min = lst[0]
for a in lst:
if key and key(a) < key(_min): _min = a
elif not key and a < _min: _min = a
return _min
def max(*args, **kwargs):
key = kwargs.get("key", None)
if len(args) < 1: return None
lst = list(args[0]) if len(args) == 1 else args
_max = lst[0]
for a in lst:
if key and key(a) > key(_max): _max = a
elif not key and a > _max: _max=a
return _max
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert max(3, 2) == 3, "Simple case max"
assert min(3, 2) == 2, "Simple case min"
assert max([1, 2, 0, 3, 4]) == 4, "From a list"
assert min("hello") == "e", "From string"
assert max(2.2, 5.6, 5.9, key=int) == 5.6, "Two maximal items"
assert min([[1, 2], [3, 4], [9, 0]], key=lambda x: x[1]) == [9, 0], "lambda key"
Nov. 24, 2015
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