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First solution in Clear category for Min and Max by werepire
def min(*args, **kwargs):
key = kwargs.get("key", None)
if (len(args))==1:
li=list(args[0])
else:
li=list(args)
mini=li[0]
for i in range (1, len(li)):
if key==None:
if li[i]maxi:
maxi=li[i]
else:
if key(li[i])>key(maxi):
maxi=li[i]
return maxi
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert max(3, 2) == 3, "Simple case max"
assert min(3, 2) == 2, "Simple case min"
assert max([1, 2, 0, 3, 4]) == 4, "From a list"
assert min("hello") == "e", "From string"
assert max(2.2, 5.6, 5.9, key=int) == 5.6, "Two maximal items"
assert min([[1, 2], [3, 4], [9, 0]], key=lambda x: x[1]) == [9, 0], "lambda key"
Oct. 19, 2016