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Second solution in Clear category for Min and Max by thealfest1
def min(*args, **kwargs):
kwargs['reverse'] = 0
return max(*args, **kwargs)
def max(*args, **kwargs):
return sorted(iter(args[0]) if len(args) == 1 else args,
key = kwargs.get('key', None), reverse = kwargs.get('reverse', 1))[0]
Feb. 7, 2019
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