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sorted solution in Clear category for Min and Max by mplichta
def min(*args, **kwargs):
key = kwargs.get('key', None)
rev = kwargs.get('rev', False)
return sorted(args if len(args) > 1 else args[0], key=key, reverse=rev)[0]
def max(*args, **kwargs):
key = kwargs.get('key', None)
return min(*args, key=key, rev=True)
March 23, 2018