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First solution in Clear category for Min and Max by PythOff
def min(*args, **kwargs):
key = kwargs.get("key", None)
try:
tab = list(*args)
except TypeError:
tab = args
# try:
# iterator = iter(tab[0])
# except TypeError:
# tab = tab
# else:
# tab = tab[0]
if key != None:
result = tab[0]
for i in range (1, len(tab)):
if key(tab[i]) < key(result):
result = tab[i]
else:
result = tab[0]
for i in range (1, len(tab)):
if tab[i] < result:
result = tab[i]
return result
def max(*args, **kwargs):
key = kwargs.get("key", None)
try:
tab = list(*args)
except TypeError:
tab = args
# try:
# iterator = iter(tab[0])
# except TypeError:
# tab = args
# else:
# tab = args[0]
if key != None:
result = tab[0]
for i in range (1, len(tab)):
if key(tab[i]) > key(result):
result = tab[i]
else:
result = tab[0]
for i in range (1, len(tab)):
if tab[i] > result:
result = tab[i]
return result
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert max(3, 2) == 3, "Simple case max"
assert min(3, 2) == 2, "Simple case min"
assert max([1, 2, 0, 3, 4]) == 4, "From a list"
assert min("hello") == "e", "From string"
assert max(2.2, 5.6, 5.9, key=int) == 5.6, "Two maximal items"
assert min([[1, 2], [3, 4], [9, 0]], key=lambda x: x[1]) == [9, 0], "lambda key"
assert min(abs(i) for i in range (-10,10)) == 0, "test 4/4"
Oct. 22, 2016